KCSE 2019 MATHEMATICS PAPER 2
KCSE 2019
KCSE 2019
KCSE 2019 MATHEMATICS PAPER 2
Uranga Maths Variation
Uranga Maths Variation
KCSE 2019 MATHEMATICS PAPER 2
KCSE 2019
KCSE 2019
KCSE
KCSE 2019
KCSE 2019
KCSE 2019 MATHEMATICS PAPER 2
KCSE 2019
KCSE 2019
KCSE 2019 MATHEMATICS PAPER 2
KCSE MATHS
KCSE 2019 MATHS
MATHEMATICS
KCSE 2019
MATHEMATICS
KCSE REVISION
KCSE REVISION
KCSE
mathematics
kcse maths paper 2 2019
kcse maths paper 2 2019
Ratios and Proportions
KCSE 2020 PAPER 2
KCSE 2020 PAPER 2
series and sequences
KCSE 2020 PP2 Q 2
KCSE 2020 PP2 Q 2
series and sequences
Q2 Continued
Q2 Continued
Three Dimensional Geometry (Maths Paper 2 2019 No. 11 (a) )
(Maths Paper 2 2019 No. 11 (a) )
(Maths Paper 2 2019 No. 11 (a) )
Three Dimensional Geometry (Maths Paper 2 2019 No. 11 (a) )
(Maths Paper 2 2019 No. 11 (a) )
(Maths Paper 2 2019 No. 11 (a) )
Three Dimensional Geometry (Maths Paper 2 2019 No. 11 (b) )
(Maths Paper 2 2019 No. 11 (b) )
(Maths Paper 2 2019 No. 11 (b) )
Maths Topical Answering Techniques
Construction and Loci
Transformations
Transformations
Errors and Approximations
The length and breadth of a rectangular card were measured to the nearest millimetre and found to be 14.5cm and 10.6cm respectively. Find the percentage error in the perimeter. 3mks
Pmax=214.55+10.65=50.4cm
Pactual=214.5+10.6=50.2cm
Pmin=214.45+10.55=50cm
Surds
Simplify the following expression;
, giving your answer in the form
, where a, b and c are real numbers 3mks
Further Logarithms
Evaluate without using tables;
4mks
Quadratic Equation
3mks
Further Logarithms
Errors and Approximations
A student expands as , if he used the formula to evaluate
, find the percentage error in his calculation 3mks
Linear Equations
A two-digit number is such that the sum of the ones and the tens digit is ten. If the digits are reversed, the new number formed exceeds the original number by 54. Find the number. 3mks
Gradient and Equation of a Line
A line parallel to line OP shown in figure below cuts the y-axis at ( ). Find the equation of the line: 3mks
1
Quadratic Equation
(a) Complete the table below for the equation, given
. 1mk
b) Using a scale of to represent 2 units in both axes, draw the graph of
(2mks)
c) Use the graph to solve the quadratic equations:
(1mk)
i (2mks)
c) Use the graph to solve the quadratic equations:
(1mks)
(1.37, 0), (-4.38, 0)
(2mks)
Maths Topical Answering Techniques
Quadratic and cubic graphs
Maths Topical Answering Techniques
Waves
Maths Topical Answering Techniques
CF (Ogive) Curve
Maths Topical Answering Techniques
Graphs
Histogram and Frequency Polygons
Linear programming
Non-linear to linear
Maths Topical Answering Techniques
Calculations and Presentation of Work
Fractions and decimals
Squares and square roots
Commercial Arithmetics
Angles and Plane figures
Maths Topical Answering Techniques
Calculations and Presentation of Work
Cubes and cube roots
Reciprocals
Indices and Logarithms
Gradient and Equation of straight lines
Reflection and congruence
Rotation
Similarity and enlargement
Trigonometric Ratios
Equation of a Circle
Equation of a Circle Mathematics KCSE Question
The equation of a circle is given by . Determine the radius and the center of the circle.
RATES OF WORK
Mary and Jane working together can cultivate a piece of land in 6 days. Mary alone can complete the work in 15 days. After the two had worked for 4 days Mary withdrew the services . Find the time taken by Jane to complete the remaining work. 3mks
=
Area scale factor and determinant of a matrix
In a transformation, an object with area is mapped onto an image whose area is
by transformation matrix
. Find the value of
3mks
-
Formulae
Make Q the subject of the formula
RECIPROCALS
Use tables of reciprocals only to work out
Use tables of reciprocals only to work out
RECIPROCALS
Use tables of reciprocals only to work out
Use tables of reciprocals only to work out
Arithmetic progression (A.P)
An arithmetic progression is such that the first term is -5, the last term is 135 and the sum of the progression is 975. Calculate:
An arithmetic progression is such that the first term is -5, the last term is 135 and the sum of the progression is 975. Calculate:
(a)The number of terms in the series 4mks
975=65n
(b) The common difference of the progression 2mks
(b) The sum of the first three terms of a geometric progression is 27 and the first term is 36. Determine the common ratio and the value of the fourth term. 4mks
BINOMIAL EXPANSIONS
(a) Expand
(a) Expand
(b) Hence find the value of , correct to 4 decimal places when substitution is up to